Question

Pecahan campur Perbandingan. jawab pakai cara penyelesaian yang mudah dimengerti ya thx ​

Answer 1

Diketahui:

AP : PD = 2 : 1

AQ : QB = 1 : 3

CT : TD = 1 : 1

Ditanyakan:

Luas AQCTP/ Luas ABCD

Jawab:

misal sisi = x

Maka:

AP = 2/(2+1) x = (2/3)x

PD = 1/(2+1) x = (1/3)x

AQ = 1/(1+3) x = (1/4)x

QB = 3/(1+3) x = (3/4)x

CT = 1/(1+1) x = (1/2)x

TD = 1/(1+1) x = (1/2)x

Tentukan luas masing-masing bangun:

• Luas AQCTP = Luas ABCD - (Luas PTD + Luas QBC)

= (s. s) - (((1/2)PD. DT)+((1/2)QB. BC)

= (x. x) - (((1/2)(1/3)x. (1/2)x) + ((1/2)(3/4)x. x)

= x² - ((1/12)x² + (3/8)x²)

= x² - ((1/12) + (3/8)) x²

= x² - ((2/24) + (9/24)) x²

= x² - (11/24)x²

= (1 - (11/24)) x²

= ((24/24) - (11/24)) x²

= (13/24) x²

• Luas ABCD = s. s

= x. x

= x²

Bandingkan

Luas AQCPT/Luas ABCD

= (13/24)x² / x²

= (13/24) / 1

= 13/24 (D)

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DETAIL JAWABAN

Mapel: Matematika

Kelas: 7

Materi: Bab 4 - Segiempat dan Segitiga

Kata kunci: Persegi, Perbandingan, Luas

Kode Soal: 2

Kode kategorisasi: 7.2.4