d=√j²-(R1+r2)²
24=√j²-(12+6)²
24²=j²-(18)²
576=j²-324
576+324=j²
900=j²
j=√900
j=30 cm
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R = 12 CM
r = 6 cm
D = 24 cm
maka :
P² = D² + (R+r)²
P² = 24² + (12+6)²
P² = 576 + 324
P = √900
P = 30 cm
jadi jrak titik pusat adalah 30 cm
d=√j²-(R1+r2)²
24=√j²-(12+6)²
24²=j²-(18)²
576=j²-324
576+324=j²
900=j²
j=√900
j=30 cm