Question

Pangkat7log 2= a dan pangkat2 log 3=b, maka pangkat6 log 98 sama dengan? Dijawab ya makasih^^

Answer 1

6'log(98) = log(98)/log(6)
= log(7^2*2) / log(2*3)
= [log(7^2) + log(2)]/[log(2) + log(3)]
= [2*2'log(7) + 2'log(2)]/[2'log(2) + 2'log(3)]
= (2/a + 1)/(1 + b)
Kalikan dengan a, maka
= (a + 2)/(ab + a)