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log (x-3) + 2 = log(2x-5) + log 25 , syarat x >3 , x > 5/2
log (x-2) +log 100 = log (2x-5)(25)
log (x-2)(100) = log (2x-5)(25
100(x-2) = 25(2x-5)
4(x-2) = 2x- 5
4x - 8 = 2x - 5
2x= 3
x = 3/2 TM) krn x < 3
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