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12, 15, 19, 24, 30
Dari deret tersebut dapat diketahui bahwa
a = 12
b = 3
c = 1
Maka U12 adalah
U12 = a+(n-1)b + 1/2(n-1)(n-2)c
= 12 + (11)3 + 1/2 (11)(10) 1
= 12+ 33 + 110/2
= 45 + 55
= 100