Deret Geometri
u2 = 8
u5 = 64
*
u5 / u2 = 64/8
r⁵⁻² = 8 = 2³
r³ = 2³
r = 2
u7 = u5 x r²
u7 = 64 (2)²= 256
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Deret Geometri
u2 = 8
u5 = 64
*
u5 / u2 = 64/8
r⁵⁻² = 8 = 2³
r³ = 2³
r = 2
*
u7 = u5 x r²
u7 = 64 (2)²= 256