Reaksi di katoda
Ag^+ + 1e ==> Ag
e Ag = Ar/elektron
= 108/1
= 108
t = 1 jam = 3600
i = 5 A
W = e x i x t/96500
= 108 x 5 x 3600/96500
= 20,14 gram
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Reaksi di katoda
Ag^+ + 1e ==> Ag
e Ag = Ar/elektron
= 108/1
= 108
t = 1 jam = 3600
i = 5 A
W = e x i x t/96500
= 108 x 5 x 3600/96500
= 20,14 gram
Ag^++1e》Ag
e Ag =Ar / elektron
=108/1
=108
t=1 jam=3.600 detik
i=5 A
W=e×i×t/96500
W=108×5×3600/96500
W=20,14 gram
jadi masa perak yg mengendap sebanyak 20,14 gram