Question

Pada Δklm diketahui L= 6m M=4 dan ∠k = 120 tentukan
A.panjang sisi K
B.besar sudut L
C.besar sudut M

Answer 1

A) gunakan atyran cosinus : k^2 = m^2 + l^2 - 2ml cos K k^2 = 4^2 + 6^2 - 2(4)(6)cos 120 k^2 = 16 + 36 - 48 * (-1/2) k^2 = 52 + 24 k^2 = 76 k = sqrt(76) B). Gunakan aturan sinus : l/sinL = k/sinK 6/sinL = sqrt(76)/sin120 6/sinL = 10,065 sin L = 6/(10,065) sin L = 0,596 L = 36,58 derajat C) sudut M = 180 - (120 + 36,58) = 180 - 156,58 = 23,42 derajat