P trojkata = 12cm 2
a = 4cm
h= ?
oblicz ile rowna sie h i oplicz pole
prosze o pomoc daje naj
P t=12cm 2
h=?
P t =(a*h)/2
12=(4*h)/2
12=2*h
h=6
P t=(4*6)/2=12 [cm 2]
P = 12 cm^2
a = 4 cm
P=1/2 a*h
12 =1/2*4*h 2h= 12 /:2 h= 6 cm
Pole jest już znane i = 12 cm^2, zaś h wynosi 6 cm.
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P t=12cm 2
a = 4cm
h=?
P t =(a*h)/2
12=(4*h)/2
12=2*h
h=6
P t=(4*6)/2=12 [cm 2]
P = 12 cm^2
a = 4 cm
P=1/2 a*h
12 =1/2*4*h
2h= 12 /:2
h= 6 cm
Pole jest już znane i = 12 cm^2, zaś h wynosi 6 cm.