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...= (2^5 *(2^2)^3*(2^6)^4) /(2^3)^2*(2^7)^3=
= (2^5 *2^6*2^24)/(2^6*2^21)=
=(2^(5+6+24)/(2^(6+21)=
=2^35/2^27=
=2^(35-27)=
=2^8=256
b)
...=(81:3)^3/(27:9)^5=
=27^3/3^5=
=(3^3)^3/3^5=
=3^9/3^5=
=3^(9-5)=
=3^4=81