Odpowiedź:
5(4-x)-2x(x-4)=20-5x-2x²+8x=-2x²-3x+20
(3x-y)(9x²+3xy+y²)=27x³+9x²y+3xy²-9x²y-3xy²-y³=27x³-y³
2x(y-4x²)+6x(x²-y)=2xy-8x³+6x³-6xy=-2x³-4xy
(2a-1)(2-3a)-(a+5)(2-a)=4a-6a²-2+3a-2a+a²-10+5a=-5a²+10a-12
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Odpowiedź:
5(4-x)-2x(x-4)=20-5x-2x²+8x=-2x²-3x+20
(3x-y)(9x²+3xy+y²)=27x³+9x²y+3xy²-9x²y-3xy²-y³=27x³-y³
2x(y-4x²)+6x(x²-y)=2xy-8x³+6x³-6xy=-2x³-4xy
(2a-1)(2-3a)-(a+5)(2-a)=4a-6a²-2+3a-2a+a²-10+5a=-5a²+10a-12
Szczegółowe wyjaśnienie: