n=√(2p+2,25)+1,5
p=27
n=√(2*27+2,25)+1,5
n=√(54+2,25)+1,5
n=√56,25+1,5
n=7,5+1,5
n=9 <-- tyle ma boków
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27=½n(n-3)
27=½n²-1,5n
½n²-1,5n-27=0
Δ=b²-4ac=2,25+54=56,25
√Δ=7,5
n=(-b+√Δ):2a=(1,5+7,5):1=9
to 9-kąt
n=√(2p+2,25)+1,5
p=27
n=√(2*27+2,25)+1,5
n=√(54+2,25)+1,5
n=√56,25+1,5
n=7,5+1,5
n=9 <-- tyle ma boków