ojciec ma 45 lat a synowie 10 i 8 po ilu latach ojciec będzie miał tyle lat co obaj synowie razem
45 + x = 10 + x + 8 + x
45 + x = 18 + 2x
x - 2x = 18 - 45
-x = - 27
x = 27 ----------- odpowiedx
spr
ojciec ---- 45 + 27 = 72
synowie --- 10 + 27 + 8 + 27 = 18 + 54 = 72
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45 + x = 10 + x + 8 + x
45 + x = 18 + 2x
x - 2x = 18 - 45
-x = - 27
x = 27 ----------- odpowiedx
spr
ojciec ---- 45 + 27 = 72
synowie --- 10 + 27 + 8 + 27 = 18 + 54 = 72