Długość boku= 24/3=8cm h=a√3/2=8√3/2=4√3cm r=1/3h Pole = πr²=(4√3/3)²π=16/3=5 i 1/3π R=2/3h Pole opisanego=πR²=(8√3/3)²π=64/3π=21 i 1/3π
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Długość boku= 24/3=8cm
h=a√3/2=8√3/2=4√3cm
r=1/3h
Pole = πr²=(4√3/3)²π=16/3=5 i 1/3π R=2/3h
Pole opisanego=πR²=(8√3/3)²π=64/3π=21 i 1/3π