Obwód pewnego koła jest równy 6pi. Pole teg okoła jest równe ?
l = d×πP = π ×r²d = 6 cmr = 6:2 = 3P = π×3² = 9π
L=2πr
6π=2πr
r=3
P=πr²
P=3²π
P=9π
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l = d×π
P = π ×r²
d = 6 cm
r = 6:2 = 3
P = π×3² = 9π
L=2πr
6π=2πr
r=3
P=πr²
P=3²π
P=9π