September 2018 1 16 Report

oblicz

(7^{11} : 7^{3} ) *7^{4}

\sqrt{16-7}

6^{2}-(-6^{2})

wyłącz czynnik przed pierwiastek \sqrt{12}

wpisz do tabeli \sqrt[3]{3} , \pi, \sqrt{1 \frac{24}{25}},\sqrt[3]{-9},\sqrt{5\frac{1}{6}},\sqrt{5\frac{1}{16}},\sqrt{2\frac{7}{9}},\sqrt{0,04},\sqrt{0,03}

wymierne: niewymierne:

oczywiscie potem wybiore najlepsza odp :)


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.