Oblicz:
log3(16+11)=log3(70+11)=
Korzystamy z definicji logarytmu:
Jeśli log o podstawie a z b=c to a do potęgi c=b
a)
b)
log₃(16+11)=log₃27
3^x=27
3^x =3^3
x=3
log₃(70+11)=log₃81
3^x=81
3^x=3^4
x=4
loga b = c ⇔ a^c=b
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Korzystamy z definicji logarytmu:
Jeśli log o podstawie a z b=c to a do potęgi c=b
a)
b)
log₃(16+11)=log₃27
3^x=27
3^x =3^3
x=3
log₃(70+11)=log₃81
3^x=81
3^x=3^4
x=4
loga b = c ⇔ a^c=b