oblicze sume "k" poczatkowych wyrazow ciagu arytemtycznego (an) jezeli k=30 an=3n+2
a1=3x1+2=5
ak=a30=3x30+2=92
Sk=S30=[(a1+a30)/2]x30
=30(5+92)/2=15x97=1455
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a1=3x1+2=5
ak=a30=3x30+2=92
Sk=S30=[(a1+a30)/2]x30
=30(5+92)/2=15x97=1455