December 2018 2 7 Report
Obliczcie i napiszcie po kolei jak to się robi:

(-4x-3)(4x-3)+8(1- \sqrt[]{2x}) ^{2}=1

2(x+2) ^{2} - ( \sqrt{2x}-2) ^{2} \geq 0

 \left \{ {{x- \frac{4x-2}{3} \geq x-6 } \atop {1-(2x-1)(1+2x)>-2x-(2x-1)^{2} }} \right.
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