oblicz:
a)(√2+1)(√2-1)=
b)(8-5√3)(8+5√3)=
c)√π-√2)(√π+√2)(π+2)
d)(√π+1+√π-1)(√π+1-√π-1)=
a)(√2+1)(√2-1)=2-1=1
b)(8-5√3)(8+5√3)=64-75=-9
c)(√π-√2)(√π+√2)(π+2)=(π-2)(π+2)=π-4
d)(√π+1+√π-1)(√π+1-√π-1)=0
a)(√2+1)(√2-1)=2-1=1b)(8-5√3)(8+5√3)=64-75=-9c)√π-√2)(√π+√2)(π+2)=(π-2)(π+2)=π²+4d)(√π+1+√π-1)(√π+1-√π-1)=√π*0=0
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a)(√2+1)(√2-1)=2-1=1
b)(8-5√3)(8+5√3)=64-75=-9
c)(√π-√2)(√π+√2)(π+2)=(π-2)(π+2)=π-4
d)(√π+1+√π-1)(√π+1-√π-1)=0
a)(√2+1)(√2-1)=2-1=1
b)(8-5√3)(8+5√3)=64-75=-9
c)√π-√2)(√π+√2)(π+2)=(π-2)(π+2)=π²+4
d)(√π+1+√π-1)(√π+1-√π-1)=√π*0=0