Oblicz:
![-[-2a-( \frac{5}{8} a+0,4)]-[2\frac{1}{2}a+(\frac{1}{8}-1,6)]](https://tex.z-dn.net/?f=-%5B-2a-%28+%5Cfrac%7B5%7D%7B8%7D+a%2B0%2C4%29%5D-%5B2%5Cfrac%7B1%7D%7B2%7Da%2B%28%5Cfrac%7B1%7D%7B8%7D-1%2C6%29%5D "-[-2a-( \frac{5}{8} a+0,4)]-[2\frac{1}{2}a+(\frac{1}{8}-1,6)]")
ivon
![a) (y-1)( y^{2} +y+1)=y^{3}+y^{2}+y-y^{2}-y-1=y^{3}-1\\\\b) -[-2a-( \frac{5}{8} a+0,4)]-[2\frac{1}{2}a+(\frac{1}{8}-1,6)]=\\ -[-2a- \frac{5}{8} a-0,4]-[2\frac{1}{2}a+(\frac{1}{8}-1\frac{3}{5}]=\\2a+\frac{5}{8} a+0,4-[2\frac{1}{2}a+(\frac{5}{40}-1\frac{24}{40}]=\\2\frac{5}{8} a+0,4-[2\frac{1}{2}a+(-1\frac{19}{40})]=\\2\frac{5}{8} a+0,4-2\frac{1}{2}a+1\frac{19}{40}=\\2\frac{5}{8}a-2\frac{4}{8}a+\frac{4}{10}+1\frac{19}{40}=\\\frac{1}{8}a+\frac{16}{40}+1\frac{19}{40}=\\\frac{1}{8}a+1\frac{35}{40}=](https://tex.z-dn.net/?f=a%29+%28y-1%29%28+y%5E%7B2%7D+%2By%2B1%29%3Dy%5E%7B3%7D%2By%5E%7B2%7D%2By-y%5E%7B2%7D-y-1%3Dy%5E%7B3%7D-1%5C%5C%5C%5Cb%29+-%5B-2a-%28+%5Cfrac%7B5%7D%7B8%7D+a%2B0%2C4%29%5D-%5B2%5Cfrac%7B1%7D%7B2%7Da%2B%28%5Cfrac%7B1%7D%7B8%7D-1%2C6%29%5D%3D%5C%5C+-%5B-2a-+%5Cfrac%7B5%7D%7B8%7D+a-0%2C4%5D-%5B2%5Cfrac%7B1%7D%7B2%7Da%2B%28%5Cfrac%7B1%7D%7B8%7D-1%5Cfrac%7B3%7D%7B5%7D%5D%3D%5C%5C2a%2B%5Cfrac%7B5%7D%7B8%7D+a%2B0%2C4-%5B2%5Cfrac%7B1%7D%7B2%7Da%2B%28%5Cfrac%7B5%7D%7B40%7D-1%5Cfrac%7B24%7D%7B40%7D%5D%3D%5C%5C2%5Cfrac%7B5%7D%7B8%7D+a%2B0%2C4-%5B2%5Cfrac%7B1%7D%7B2%7Da%2B%28-1%5Cfrac%7B19%7D%7B40%7D%29%5D%3D%5C%5C2%5Cfrac%7B5%7D%7B8%7D+a%2B0%2C4-2%5Cfrac%7B1%7D%7B2%7Da%2B1%5Cfrac%7B19%7D%7B40%7D%3D%5C%5C2%5Cfrac%7B5%7D%7B8%7Da-2%5Cfrac%7B4%7D%7B8%7Da%2B%5Cfrac%7B4%7D%7B10%7D%2B1%5Cfrac%7B19%7D%7B40%7D%3D%5C%5C%5Cfrac%7B1%7D%7B8%7Da%2B%5Cfrac%7B16%7D%7B40%7D%2B1%5Cfrac%7B19%7D%7B40%7D%3D%5C%5C%5Cfrac%7B1%7D%7B8%7Da%2B1%5Cfrac%7B35%7D%7B40%7D%3D "a) (y-1)( y^{2} +y+1)=y^{3}+y^{2}+y-y^{2}-y-1=y^{3}-1\\\\b) -[-2a-( \frac{5}{8} a+0,4)]-[2\frac{1}{2}a+(\frac{1}{8}-1,6)]=\\ -[-2a- \frac{5}{8} a-0,4]-[2\frac{1}{2}a+(\frac{1}{8}-1\frac{3}{5}]=\\2a+\frac{5}{8} a+0,4-[2\frac{1}{2}a+(\frac{5}{40}-1\frac{24}{40}]=\\2\frac{5}{8} a+0,4-[2\frac{1}{2}a+(-1\frac{19}{40})]=\\2\frac{5}{8} a+0,4-2\frac{1}{2}a+1\frac{19}{40}=\\2\frac{5}{8}a-2\frac{4}{8}a+\frac{4}{10}+1\frac{19}{40}=\\\frac{1}{8}a+\frac{16}{40}+1\frac{19}{40}=\\\frac{1}{8}a+1\frac{35}{40}=")
1 votes
Thanks 0
More Questions From This User See All
Recommend Questions
ola737626
October 2020 | 0 Replies
BŁAGAM POMÓŻCIE PLIIIISSSSSSSS ❤️❤️❤️ DAJE ❤️ I NAJ!!!!!! BĘDĘ WDZIĘCZNA PLISSSSSSSSS...W tabeli (w załączniku) podano wyniki zakończonego sezonu szkolnej ligi piłkarskiej każda z drużyn rozegrała 10 meczów. Za wygrany mecz otrzymywała 3 punkty za remis 1 punkt a za porażkę 0 punktówWykonaj polecenie i napisz działanie Niebiescy w 10 meczach zdobyli 26 punktów. Ile razy odnieśli zwycięstwo A ile razy zremisowali