Question

oblicz:

a) [(x⁵:x³)⁴:(x³)²]⁵:(x·x³)²= x≠0

b)[(a⁷·a²):(a³)²]⁴:(a⁹:a⁶)²= a≠0

d) [(a²·b³)⁴:(a·b²)³]:[(a³·b²)²:(a⁴·b²)²]= a≠0 i b≠0

PROSZĘ o pomoc.........

Answer 1

a)[(x⁵:x³)⁴:(x³)²]⁵:(x·x³)²=  [(x²)⁴:x⁶]⁵:(x⁴)²=(x⁸:x⁶)⁵:x⁸=x²:x⁸=x⁻⁶

 

b)[(a⁷·a²):(a³)²]⁴:(a⁹:a⁶)²=[a⁹:a⁶]⁴:(a³)²=(a³ )⁴:a⁶=a¹²:a⁶=a⁶ 

 

d) [(a²·b³)⁴:(a·b²)³]:[(a³·b²)²:(a⁴·b²)²]=[(a⁸*b¹²):(a³*b⁶)]:[(a⁶*b⁴):(a⁸*b⁴)=

=(a⁵*b⁶):(a⁻²*b°)=a⁷*b⁶

 

 

Nie jestem pewna czy przykład C jest na 100% dobrze