Oblicz:
a) 2* 16 do potęgi -1,5 * 32 do potęgi 1,2 =
c)
proszę o pomoc i objaśnienie
a) 2 * 16^(-1,5) *32 ^(1,2)=
= 2 * (2^4)^(-3/2) * (2^5)^6/5 =
= 2 * 2^(-6) * 2^6 =
= 2^(1 + (-6) +6)=
=2^1=
=2
b)
...= [(49/16)^3/2 *(7/4)^2/5 *(7/4)^3/5]^1/4=
=[ ((7/4)^2)^3/2 * (7/4)^2/5 * (7/4)^3/5] ^1/4=
=[ (7/4)^(3+2/5+3/5)]^1/4=
=[(7/4)^4]^1/4=
=(7/4)^4/4=
= (7/4)^1=
= 7/4=
= 1 3/4
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a) 2 * 16^(-1,5) *32 ^(1,2)=
= 2 * (2^4)^(-3/2) * (2^5)^6/5 =
= 2 * 2^(-6) * 2^6 =
= 2^(1 + (-6) +6)=
=2^1=
=2
b)
...= [(49/16)^3/2 *(7/4)^2/5 *(7/4)^3/5]^1/4=
=[ ((7/4)^2)^3/2 * (7/4)^2/5 * (7/4)^3/5] ^1/4=
=[ (7/4)^(3+2/5+3/5)]^1/4=
=[(7/4)^4]^1/4=
=(7/4)^4/4=
= (7/4)^1=
= 7/4=
= 1 3/4