September 2018 1 18 Report

oblicz:

(2*(2*\frac{5}{7})^{2} - ( 3^{0} - 1\frac{2}{7})=</p> <p> (1-2\frac{1}{2})^{3}-( -2)^{2}=</p> <p> (1\frac{1}{4})^{2} + (1\frac{1}{2})^{4}= </p> <p>(1\frac{1}{5}+\frac{7}{15})^{2}-(5*\frac{1}{3})^{2}=</p> <p> [tex][(-\frac{2}{3})^{2} : \frac{8}{9}]^{2}= </p> <p>(1\frac{1}{7})^{2}*(\frac{7}{4})^{2}-[(-2)*(\frac{1}{2})^{2}]*(-1)=</p> <p>[tex][(\frac{3}{4})^{2}*\frac{12}{9}]^{2}+(1\frac{1}{3})^{0}*[(\frac{3}{2})^{2}*\frac{2}{3}]=</p> <p>[tex][1+(\frac{5}{3})^{2}*(-\frac{3}{5})^{3}*(2\frac{1}{3})^{5}kreska\ ulamkowa(\frac{7}{3})^{4}]-(\frac{3}{4})^{0}=</p> <p>[tex][1+(\frac{2}{3})^{2}*\frac{3}{4}]^{2}kreska\ ułamkowa(3-1\frac{2}{3})^{3}-)2\frac{1}{2}*\frac{1}{5})^{2}=</p> <p>[tex]oblicz\ ile\ razy \ liczba\ a\ jest\ mniejsza \ od \ b\ jezeli \ : a=(2^{7}-5*2^{4}):1\frac{1}{2}kreska\ ulakowa 3*2^{5}-2^{4} b=(3^{33}-3*3^{31}):@\frac{4}{5}kreska\ ułamkowa9^{15}*1\frac{1}{4}

rozwiaz uklad rownan algebraicznie i graficznie:

\left \{ {{(x-2)^{2}-2(x-2y)=1-(3-x)*(3+x)} \atop {2x+y=4}} \right


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