Oblicz zawartosc procentowa wodoru w etynie,etanie i etenie.
Etan: C2H6
mcz = 24 u + 6 u = 30 u
%H= 6u/30u x 100% = 20%
Eten:C2H4
mcz = 24u + 4u= 28 u
%H = 4u/28u x 100% = 14%
Etyn: C2H2
mcz= 24 u + 2 u = 26 u
%H = 2u/26u x 100 % = 8%
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Etan: C2H6
mcz = 24 u + 6 u = 30 u
%H= 6u/30u x 100% = 20%
Eten:C2H4
mcz = 24u + 4u= 28 u
%H = 4u/28u x 100% = 14%
Etyn: C2H2
mcz= 24 u + 2 u = 26 u
%H = 2u/26u x 100 % = 8%