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m C4H10- 4x12u+10x1u= 58u
m Węgla- 4x12u= 48u
% 48:58 x 100%= 82 22:29 %
mC4H10= 4*12u + 10*1u= 48 u +10u=58u
%C=48u/58u*100%= 82,76%
Zawartość węgla w tym związku wynosi 82,76%