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Wodorotlenek litu - LiOH.
Obliczamy masę cząsteczkową:
m LiOH = 7[u] + 17[u = 24[u].
[%] Li = (7[u] +100[%]) / 24[u] = 29,2[%] - litu.
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m (masa atomowa) Li = 7u
m O = 16u
m H = 1u
m. cz (masa cząsteczkowa) LiOH= 7u + 16u + 1u = 24u
24u LiOH----------stanowi---------100%
to 7u Li-------------stanowi----------X%
X= 7u * 100% : 24u ≈ 29,17% litu