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log[3/12] = log[3/(4*3)] = log[3/4] + log[3/3] = log[3/(2^2)] + 1 = 2log[3/2] + 1
= 2a + 1
log[3/36] = log[3/(4*9)] = log[3/4] + log[3/9] = 2a + 2.