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Dane: a = 10, dlugosci przekatnych: d₁ = 2·6 = 12, d₂ = 2·8 = 16, h = ?
Pole rombu: P = ½ · d₁ · d₂ = ½ · 12 · 16 = 6·16 = 96.
Pole rombu jest takze rowne: P = a · h
Zatem: 10· h = 96 /:10
h = 9,6
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Dane: a = 10, dlugosci przekatnych: d₁ = 2·6 = 12, d₂ = 2·8 = 16, h = ?
Pole rombu: P = ½ · d₁ · d₂ = ½ · 12 · 16 = 6·16 = 96.
Pole rombu jest takze rowne: P = a · h
Zatem: 10· h = 96 /:10
h = 9,6