Oblicz wysokość trójkąta równobocznego o boku: a) 12 b) 5 c) √3 d) 4√6
h=aV3/2
a)
a=12
h=12V3/2=6V3
b)
a=5
h=5V3/2=2,5V3
c)
a=V3
h=V3*V3/2=3/2=1,5
d)
a=4V6
h=4V6*V3/2=2*V9=2*3=6
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h=aV3/2
a)
a=12
h=12V3/2=6V3
b)
a=5
h=5V3/2=2,5V3
c)
a=V3
h=V3*V3/2=3/2=1,5
d)
a=4V6
h=4V6*V3/2=2*V9=2*3=6