Oblicz wysokość rombu, którego przekątne mają 12 cm i 16 cm, a bok ma 10 cm.
KLASA 5 Z OBLICZENIAMI
P = 0,5ef
P = 0,5*12cm*16cm = 96cm²
P = ah
96cm² = 10cm * h
h = 9,6cm
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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P = 0,5ef
P = 0,5*12cm*16cm = 96cm²
P = ah
96cm² = 10cm * h
h = 9,6cm
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)