Oblicz wartość wyrażenia : log⅔4 - 2log⅔3
Daje naj!
log 2/3 4 - log 2/3 3^2=
log 2/3 4 - log 2/3 9=
log 2/3 4/9=
2
log(2/3) 4 - 2log(2/3) 3 = log(2/3) 4 - log(2/3) 3^2 = log(2/3) 4 - log(2/3) 9 =
log(2/3) (4 : 9) = log(2/3) 4/9 = log(2/3) (2/3)^2 = 2 *log(2/3) 2/3 = 2 * 1 = 2
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log 2/3 4 - log 2/3 3^2=
log 2/3 4 - log 2/3 9=
log 2/3 4/9=
2
log(2/3) 4 - 2log(2/3) 3 = log(2/3) 4 - log(2/3) 3^2 = log(2/3) 4 - log(2/3) 9 =
log(2/3) (4 : 9) = log(2/3) 4/9 = log(2/3) (2/3)^2 = 2 *log(2/3) 2/3 = 2 * 1 = 2