Oblicz wartość wyrażenia dla x=pierwiastek z 3
(x+1)(x-1)+(x+2)(x-2)-(x+3)(x-3)=?
(x²-1)+(x²-4)-(x²-9)=3-1+3-4-3+9=7
(x+1)(x-1)+(x+2)(x-2)-(x+3)(x-3)= (x^2 - 1) + (x^2 - 4) - (x^2 - 9) = x^2 - 1 + x^2 - 4 - x^2 + 9 = x^2 + 4
(√3)^2 + 4 = 3 + 4 = 7
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(x²-1)+(x²-4)-(x²-9)=3-1+3-4-3+9=7
(x+1)(x-1)+(x+2)(x-2)-(x+3)(x-3)= (x^2 - 1) + (x^2 - 4) - (x^2 - 9) = x^2 - 1 + x^2 - 4 - x^2 + 9 = x^2 + 4
(√3)^2 + 4 = 3 + 4 = 7