Oblicz wartość wyrażeń algebraicznych .
3 x + 1 x = - 1
5 - 2 y y = 1
a ( 2 a + 1 ) a = 1
S do kwadratu - 1 S = - 3
2 ( x - y ) x = - 3 , y = 4
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3 x + 1 x = - 1
3*(-1)+1=-3+1=-2
5 - 2 y y = 1
5-2*1=5-2=3
a ( 2 a + 1 ) a = 1
1(2*1+1)=2+1=3
S do kwadratu - 1 S = - 3
(-3)^2-1=9-1=8
2 ( x - y ) x = - 3 , y = 4
2(-3-4)=2*(-7)=-14
licze na naj
3 x + 1 x = - 1
-1 *3 +1 = -3 + 1=-2
5 - 2 y y = 1
5 - 2*1 = 5 - 2 = 3
a ( 2 a + 1 ) a = 1
1 (2*1 + 1) = 2+1 = 3
- 1 S = - 3
-1 = 9-1 = 8
2 ( x - y ) x = - 3 , y = 4
2 (-3-4) = 2 * (-7) = -14