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m(alkoholu)= 100-12=88u
CnH2n+1OH-----> wzór ogólny na alkohole monohydroksyolwe
12n+2n+1+17=88
14n=88-18
14n=70/:14
n=5
wzór alkoholu: CH3-CH2-CH2-CH2-CH2-OH
mC=5*12=60u
mH=12u
mO=16u
C/H/O=60/12/16
C/H/O=15/3/4