oblicz sume dziesięciu początkowych wyrzów jesli
s2= -1
r= 5
S₂=-1
r=5
S₂=a₁+a₂=a₁+a₁+r
a₁+a₁+r=-1
2a₁+5=-1
2a₁=-1-5
2a₁=-6 /:2
a₁=-3
a₁₀=a₁+9r=-3+9*5=-3+45=42
Odp. S₁₀=195.
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S₂=-1
r=5
S₂=a₁+a₂=a₁+a₁+r
a₁+a₁+r=-1
2a₁+5=-1
2a₁=-1-5
2a₁=-6 /:2
a₁=-3
a₁₀=a₁+9r=-3+9*5=-3+45=42
Odp. S₁₀=195.