Oblicz stosunek masy węgla do masy wodoru i do masy tlenu w sacharozie.
sacharoza - C₁₂H₂₂O₁₁
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mC₁₂H₂₂O₁₁=144u+22u+176u=342u
mC : mH : mO = 144 : 22 : 176
mC : mH : mO = 72 : 11 : 88
mC ------>144
mH------->22
mO------>176
144/22/176
72 /11 / 88