oblicz stosunek masowy węgla do tlenu w butanie
Butan = C₄H₁₀
m(C₄H₁₀) = 4 * 12u + 10 * 1 u = 48 u + 10 u = 58 u
stosunek masowy C:H=48:10
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Butan = C₄H₁₀
m(C₄H₁₀) = 4 * 12u + 10 * 1 u = 48 u + 10 u = 58 u
stosunek masowy C:H=48:10