Oblicz stezenie jonow h+ przy ktorym zaczyna sie wytracac osad fe(oh)2 z roztwory fecl2 o stezeniu 10^-2. Ksofeoh2= 7,94*10^-16
Rammar515
![[FeCl_{2}] = [Fe^{2+}]](https://tex.z-dn.net/?f=%5BFeCl_%7B2%7D%5D+%3D+%5BFe%5E%7B2%2B%7D%5D "[FeCl_{2}] = [Fe^{2+}]")
mol/dm3
mol/dm3
![[OH^{-}] = 2 * 1,41 * 10^{-7} = 2,82 * 10^{-7}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D+%3D+2+%2A+1%2C41+%2A+10%5E%7B-7%7D+%3D+2%2C82+%2A+10%5E%7B-7%7D "[OH^{-}] = 2 * 1,41 * 10^{-7} = 2,82 * 10^{-7}")
mol/dm3
![[H^{+}] * [OH^{-}] = 10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D+%2A+%5BOH%5E%7B-%7D%5D+%3D+10%5E%7B-14%7D "[H^{+}] * [OH^{-}] = 10^{-14}")
![[H^{+}] = \frac{10^{-14}}{2,82 * 10^{-7}} = 3,55 * 10^{-8}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D+%3D+%5Cfrac%7B10%5E%7B-14%7D%7D%7B2%2C82+%2A+10%5E%7B-7%7D%7D+%3D+3%2C55+%2A+10%5E%7B-8%7D "[H^{+}] = \frac{10^{-14}}{2,82 * 10^{-7}} = 3,55 * 10^{-8}")
mol/dm3
3 votes
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