Oblicz stężenie molowe roztworu jeżeli w 1cm3 kwasu ortofosforowego 5 zawartych jest 16mg tego kwasu
M H₃PO₄ - 98g/mol
m16mg = 0,016g
n = m/M
V = 1cm³ = 0,001dm³
cm = n/V = m/MV
cm = 0,016g/98g/mol x 0,001dm³ = 0,16mol/dm³
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
Cm=? V=1cm3=0,001dm3 m=16mg=0,016g
Cm=n/V
n=m/M
MH3PO4=3+31+64=98g/mol
n=0,016g/98g/mol
n=0,0001632mol
Cm=0,0001632mol/0,001dm3
Cm=0,16mol/dm3
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M H₃PO₄ - 98g/mol
m16mg = 0,016g
n = m/M
V = 1cm³ = 0,001dm³
cm = n/V = m/MV
cm = 0,016g/98g/mol x 0,001dm³ = 0,16mol/dm³
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
Cm=? V=1cm3=0,001dm3 m=16mg=0,016g
Cm=n/V
n=m/M
MH3PO4=3+31+64=98g/mol
n=0,016g/98g/mol
n=0,0001632mol
Cm=0,0001632mol/0,001dm3
Cm=0,16mol/dm3