Oblicz stężenie molowe roztworu jeżeli w 400cm3 tego roztworu kwasu solnego jest rozpuszczone 3,65 g tego kwasu.
Cm=? V=400cm3=0,4dm3 m=3,65g
Cm=n/V
n=m/M
MHCl=1+35,5=36,5g/mol
n=3,65g/36,5g/mol
n=0,1mol
Cm=0,1mol/0,4dm3
Cm=0,25mol/dm3
M HCl = 36,5g/mol
m = 3,65g
n = m/M
n = 3,65g/36,5g/mol = 0,1mola
V = 400cm³ = 0,4dm³
cm = n/V
cm = 0,1mola/0,4dm³ = 0,25mol/dm³
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Cm=? V=400cm3=0,4dm3 m=3,65g
Cm=n/V
n=m/M
MHCl=1+35,5=36,5g/mol
n=3,65g/36,5g/mol
n=0,1mol
Cm=0,1mol/0,4dm3
Cm=0,25mol/dm3
M HCl = 36,5g/mol
m = 3,65g
n = m/M
n = 3,65g/36,5g/mol = 0,1mola
V = 400cm³ = 0,4dm³
cm = n/V
cm = 0,1mola/0,4dm³ = 0,25mol/dm³
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)