Oblicz skład procentowy tlenku baru.
mBaO=137u+16u=153u
%Ba=137u/153u * 100%
%Ba=89,5%
%O=16u/153u * 100%
%O=10,5%
%Ba = (137/153)*100% = 89,5% Ba
%O = (16/153)*100% = 10,5% O
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mBaO=137u+16u=153u
%Ba=137u/153u * 100%
%Ba=89,5%
%O=16u/153u * 100%
%O=10,5%
mBaO=137u+16u=153u
%Ba = (137/153)*100% = 89,5% Ba
%O = (16/153)*100% = 10,5% O