P=30cm²
pole koła=πr²
r²=30/π
r=√30/π r=30/3,14 r≈3,09(cm)
P=520m²
r=√520/π r=520/3,14 r≈12,87 (m)
P=2km²
r=√2/π r=2/3,14 r≈0,63 (km) / ----- kreska ułamkowa
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P=30cm²
pole koła=πr²
r²=30/π
r=√30/π r=30/3,14 r≈3,09(cm)
P=520m²
r=√520/π r=520/3,14 r≈12,87 (m)
P=2km²
r=√2/π r=2/3,14 r≈0,63 (km) / ----- kreska ułamkowa
a)
30 = πr²
30 = 3,14r²
r² = 9,55
r ≈3,09 cm
b)
520 = πr²
520 = 3,14r²
r²=165,61
r ≈ 12,87m
c)
2 = 3,14r²
r² = 0,64
r ≈ 0,8 km = 800 m