Oblicz promien okregu opisanego na trojkacie o dlugosciach bokow 6,10 14.
P=a*b*c/4rwyznaczamy promieńr=a*b*c/4Pr=14*10*6/4*26r=840j3/102r=8,2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=a*b*c/4r
wyznaczamy promień
r=a*b*c/4P
r=14*10*6/4*26
r=840j3/102
r=8,2