Oblicz promień r okręgu wpisanego w trójkąt prostokątny ABC o wierzchołkach:
A=(1,0)
B=(3,2)
C=(7,-2)
AB=√[(3-1)²+(2-0)²]=√8=2√2
AC=√[(7-1)²+(-2-0)²]=√40=2√10
BC=√[(7-3)²+(-2-2)²]=√32=4√2
a=2√2
b=4√2
c=2√10
r=½(2√2+4√2-2√10)=½[ 6√2-2√10]=3√2-√10
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AB=√[(3-1)²+(2-0)²]=√8=2√2
AC=√[(7-1)²+(-2-0)²]=√40=2√10
BC=√[(7-3)²+(-2-2)²]=√32=4√2
a=2√2
b=4√2
c=2√10
r=½(2√2+4√2-2√10)=½[ 6√2-2√10]=3√2-√10