Oblicz procentową zawartość tlenu w occie wapnia
Proszę szybko z góry dziękuję ;******
m(CH3COO)2Ca=158u
%O = (64/158)*100% = 40,51%
Chyba chodziło Ci o octan wapnia- (CH3COO)2Ca
m(CH3COO)2Ca=4*12u+6*1u+4*16u+40u
64u-x%
158u-100%
x=40,51%O
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m(CH3COO)2Ca=158u
%O = (64/158)*100% = 40,51%
Chyba chodziło Ci o octan wapnia- (CH3COO)2Ca
m(CH3COO)2Ca=4*12u+6*1u+4*16u+40u
m(CH3COO)2Ca=158u
64u-x%
158u-100%
x=40,51%O