Oblicz Pp,Pc i V ostrosłupa prawidłowego czworokątnego,którego krawędź podstawy ma 10cm,a krawędź boczna ma 6cm
Pp = 10 * 10 = 100 cm^2
Pc=2*pp+Pb=2*100 + 4* 6 *10=200+240=440 cm^2
V=Pp * H= 100 * 6=600 cm^3
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Pp = 10 * 10 = 100 cm^2
Pc=2*pp+Pb=2*100 + 4* 6 *10=200+240=440 cm^2
V=Pp * H= 100 * 6=600 cm^3