Oblicz potęgi.
a)
b)
d)
e)
f)
g)
h)
i)
j)
k)
l)
zapisz liczby w postaci o wykładniku ulemnym
i)0,9=
j) 2,56=
a) =1/3
b) =(-1/5)²=1/25
c) =(-1/4)³=-1/64
d) = (1/2)⁴=1/16
e) = (5/2)³=125/8
f) = (3/11)²=9/121
g) =2/3
h) =(-3/7)²=9/49
i) =5³=125
j) =(2/3)³=8/27
k) =5/17
l) =(-5/6)=25/36
==================
g) =(7/2)⁻¹=(3,5)⁻¹
h) =125/27=(5/3)³=(3/5)⁻³
i) =9/10=(10/9)⁻¹
j) =256/100=64/25=(8/5)²=(5/8)⁻²
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a) =1/3
b) =(-1/5)²=1/25
c) =(-1/4)³=-1/64
d) = (1/2)⁴=1/16
e) = (5/2)³=125/8
f) = (3/11)²=9/121
g) =2/3
h) =(-3/7)²=9/49
i) =5³=125
j) =(2/3)³=8/27
k) =5/17
l) =(-5/6)=25/36
==================
g) =(7/2)⁻¹=(3,5)⁻¹
h) =125/27=(5/3)³=(3/5)⁻³
i) =9/10=(10/9)⁻¹
j) =256/100=64/25=(8/5)²=(5/8)⁻²