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P=2²=4
pole koła= πr²
p=π
pole zacieniowanej figury= 4-π
r =1cm
Pkw=2cmx2cm=4cm²
Pko=(1cm)²π =1πcm²
Pz (zamalowanej figury) = 4cm² -1πcm²
Jeśli π=3,14
Pz = 4cm²-3,14cm² = 0,86cm²