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P= 126/360 * 3,14 * 100
P= 126/360 * 314
P = 0,35 * 314
P = 109,9
Nie jestem pewnaa ale chyba tak ;)
P=πx100x126/360
P=πx1260/36
P=35π cm²
Odp: Pole wycinka kołowego wynosi 35πcm²